03php拉取服务器信息并生成json

<?php$servername = "服务器";$username = "用户名";$password = "密码";$dbname = "数据库名称";$con =mysqli_connect($servername, $username, $password, $dbname);$sql =
posted @ 2020-01-11 22:20  tenas1985  阅读(175)  评论(0)  编辑  收藏  举报