linux缓冲区溢出尝试

#include <stdio.h>#include <string.h>char Lbuffer[] = "01234567890123456789 ABCD";void foo(){ char buff[16]; strcpy (buff, Lbuffer);}int main(int argc
posted @ 2020-06-02 19:45  big螺丝  阅读(241)  评论(0编辑  收藏  举报