stringpath=@"C:\Program Files";System.Diagnostics.Process.Start("explorer.exe", path);===========打开当前程序的文件夹目录 string path = Application.StartupPath; System.Diagnostics.Process.Start("explorer.exe", path); Read More
posted @ 2011-12-16 22:20 秦小米 Views(916) Comments(0) Diggs(0) Edit