When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ \begin{equation}\label{eq6}[x_{ Read More
posted @ 2020-03-20 22:30 break_happy Views(486) Comments(0) Diggs(0) Edit